Math Problem Statement

F(x)=x^2-3x G(x)=x-3 Find f of g

Solution

To find f(g(x))f(g(x)), also known as the composition fg(x)f \circ g(x), you substitute g(x)g(x) into f(x)f(x).

Given:

  • f(x)=x23xf(x) = x^2 - 3x
  • g(x)=x3g(x) = x - 3

Step-by-step:

  1. Start by substituting g(x)=x3g(x) = x - 3 into f(x)f(x).

    f(g(x))=f(x3)f(g(x)) = f(x - 3)

  2. Now, replace every occurrence of xx in f(x)=x23xf(x) = x^2 - 3x with (x3)(x - 3).

    f(x3)=(x3)23(x3)f(x - 3) = (x - 3)^2 - 3(x - 3)

  3. Simplify:

    (x3)2=x26x+9(x - 3)^2 = x^2 - 6x + 9 3(x3)=3x+9-3(x - 3) = -3x + 9

  4. Combine the terms:

    f(g(x))=x26x+93x+9f(g(x)) = x^2 - 6x + 9 - 3x + 9 f(g(x))=x29x+18f(g(x)) = x^2 - 9x + 18

Thus, f(g(x))=x29x+18f(g(x)) = x^2 - 9x + 18.

Would you like further clarification or more details on any step?

Here are 5 related questions:

  1. How do you find g(f(x))g(f(x))?
  2. What is the domain of the function f(g(x))f(g(x))?
  3. Can you graph ( f

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Math Problem Analysis

Mathematical Concepts

Algebra
Function Composition
Quadratic Equations

Formulas

f(g(x)) = f(x - 3) = (x - 3)^2 - 3(x - 3)
Quadratic expansion: (x - 3)^2 = x^2 - 6x + 9

Theorems

Function Composition

Suitable Grade Level

Grades 8-10