Math Problem Statement

a simple function defined in R2 that belongs to class C1 in R2 but not to class C2 in R2 you don’t need to be overly detailed as to why your function is C1 and not C2,

Solution

A simple example of a function f:R2Rf : \mathbb{R}^2 \to \mathbb{R} that belongs to class C1C^1 but not to class C2C^2 is:

f(x,y)=xyf(x, y) = |x| \cdot y

This function is C1C^1 in R2\mathbb{R}^2 (i.e., it is continuous and has continuous first partial derivatives), but it is not C2C^2 because its second partial derivatives are not continuous at x=0x = 0. Specifically, the mixed partial derivative 2fxy\frac{\partial^2 f}{\partial x \partial y} is not continuous at x=0x = 0.

Let me know if you'd like more explanation or if you have any other questions!

Follow-up questions:

  1. Can you explain the difference between C1C^1 and C2C^2 functions in more detail?
  2. How can you check whether a function is continuous or differentiable in R2\mathbb{R}^2?
  3. How do second-order partial derivatives impact the classification of a function as C2C^2?
  4. Can the function f(x,y)=xyf(x, y) = |x| \cdot y be modified to be C2C^2?
  5. What are some typical examples of C2C^2 functions in multivariable calculus?

Tip: In multivariable calculus, checking whether the function is continuously differentiable at the boundary (such as at x=0x = 0) is often the key to determining whether it's in C2C^2.

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Math Problem Analysis

Mathematical Concepts

Calculus
Multivariable Functions
Class C1 and C2 Functions

Formulas

f(x, y) = |x| * y

Theorems

Continuity of partial derivatives
Mixed partial derivatives

Suitable Grade Level

College-level Calculus