Math Problem Statement

A 87.8-kg baseball player slides into second base. The coefficient of kinetic friction between the player and the ground is Hk = 0.600. (a) What is the magnitude of the frictional force? (b) If the player comes to rest after 1.23 s, what is his initial speed?

Solution

To solve this problem, let's break it down into two parts:

Part (a) - Magnitude of the Frictional Force

The frictional force FfF_f is given by the equation:

Ff=μkNF_f = \mu_k \cdot N

where:

  • μk\mu_k is the coefficient of kinetic friction (0.600),
  • NN is the normal force, which is equal to the gravitational force acting on the player since he is sliding on a horizontal surface.

The gravitational force is:

N=mgN = m \cdot g

where:

  • mm is the mass of the player (87.8 kg),
  • gg is the acceleration due to gravity (9.81 m/s²).

Substitute the values:

N=87.8kg9.81m/s²=860.418NN = 87.8 \, \text{kg} \cdot 9.81 \, \text{m/s²} = 860.418 \, \text{N}

Now, calculate the frictional force:

Ff=0.600860.418N=516.251NF_f = 0.600 \cdot 860.418 \, \text{N} = 516.251 \, \text{N}

Thus, the magnitude of the frictional force is approximately 516.25 N.


Part (b) - Initial Speed of the Player

To find the initial speed, we use the fact that the player comes to rest under the influence of the frictional force. The frictional force causes a deceleration aa, which can be found from Newton's second law:

Ff=maF_f = m \cdot a

Rearranging for acceleration aa:

a=Ffm=516.251N87.8kg=5.88m/s²a = \frac{F_f}{m} = \frac{516.251 \, \text{N}}{87.8 \, \text{kg}} = 5.88 \, \text{m/s²}

Since the player comes to rest after 1.23 seconds, we can use the equation of motion:

vf=vi+atv_f = v_i + a \cdot t

where:

  • vfv_f is the final velocity (0 m/s, since the player comes to rest),
  • viv_i is the initial velocity (what we need to find),
  • aa is the deceleration (-5.88 m/s²),
  • tt is the time (1.23 s).

Rearranging to solve for viv_i:

vi=vfatv_i = v_f - a \cdot t

Substitute the known values:

vi=0(5.88m/s²)1.23s=7.23m/sv_i = 0 - (-5.88 \, \text{m/s²}) \cdot 1.23 \, \text{s} = 7.23 \, \text{m/s}

Thus, the initial speed of the player is approximately 7.23 m/s.


Summary of Answers:

(a) The magnitude of the frictional force is 516.25 N.
(b) The player's initial speed was 7.23 m/s.


Would you like more details or have any questions about these calculations?

Here are 5 related questions to deepen your understanding:

  1. How would the frictional force change if the coefficient of friction increased?
  2. What happens to the initial speed if the mass of the player decreases?
  3. How would the time to come to rest affect the calculated initial speed?
  4. What other forces, if any, act on the player during the slide?
  5. How would the problem change if the surface was inclined?

Tip: Always ensure the direction of forces matches the coordinate system when applying Newton’s laws.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Physics
Kinematics
Newton's Laws
Friction

Formulas

Frictional force F_f = μ_k * N
Normal force N = m * g
Newton's second law F = m * a
Equation of motion v_f = v_i + a * t

Theorems

Newton's Second Law

Suitable Grade Level

Grades 11-12