The function provided is:

$h(t) = -16t^2 + 100$

where $h(t)$ gives the height of the tool in feet at time $t$ seconds after it was dropped.

To find the height of the tool at $t = 2$ seconds, substitute $t = 2$ into the function:

$h(2) = -16(2)^2 + 100$

$h(2) = -16(4) + 100 = -64 + 100 = 36$

Thus, the height of the tool after 2 seconds is 36 feet.

Would you like further details or explanations on this?

Here are 5 related questions you could explore:

1. What is the height of the tool at $t = 0$?
2. How long will it take for the tool to hit the ground (i.e., when $h(t) = 0$)?
3. What is the maximum height reached by the tool if it had been thrown upwards initially?
4. How would the height change if the platform were higher (changing the constant)?
5. How would the height change if air resistance were included in the model?

Tip: Quadratic functions like this often model free fall, where the negative coefficient represents the effect of gravity pulling the object down.