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The problem asks how much more of the cake the boys ate compared to the girls. The boys ate \( \frac{5}{9} \) of the cake, while the girls ate \( \frac{1}{3} \) of the cake.

### Step 1: Find a common denominator
The least common denominator (LCD) between 9 and 3 is 9.

- Rewrite \( \frac{1}{3} \) with a denominator of 9:  
  \( \frac{1}{3} = \frac{3}{9} \).

### Step 2: Subtract the fractions
Now subtract \( \frac{3}{9} \) from \( \frac{5}{9} \):

\[
\frac{5}{9} - \frac{3}{9} = \frac{2}{9}
\]

Thus, the boys ate \( \frac{2}{9} \) more of the cake than the girls.

### Answer:
The correct answer is \( \frac{2}{9} \), which corresponds to the last option.

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Would you like more details or have any questions?

Here are 5 related questions to consider:
1. How do you find the least common denominator for two fractions?
2. What are the steps for subtracting fractions with different denominators?
3. How can you check if your subtraction of fractions is correct?
4. How would the result change if the girls ate \( \frac{2}{3} \) of the cake instead?
5. What if the boys ate \( \frac{7}{9} \) of the cake and the girls ate \( \frac{4}{9} \)?

**Tip:** Always simplify fractions before performing operations to avoid mistakes.

At Jamie’s birthday party, the boys ate 5/9 of the cake, and the girls ate 1/3 of the cake. How much more of the cake did the boys eat than the girls?

Learn how to subtract fractions with different denominators by finding the least common denominator (LCD). This problem involves comparing how much more of the cake the boys ate (5/9) compared to the girls (1/3). Suitable for students in Grades 4-6.

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