Let me analyze the content of the image to provide a solution.

Problem:

• Mary bought 9/10 meters of ribbon.
• She used 5/6 meters to tie a present.
• With the remaining ribbon, she made 3 bows.
• We need to find how much ribbon was used to make 1 bow.

Solution:

1. Step 1: Find the remaining ribbon after tying the present
   Total ribbon Mary started with: $\frac{9}{10}$ meters.
   Ribbon used to tie the present: $\frac{5}{6}$ meters.

   To find the remaining ribbon: $\text{Remaining ribbon} = \frac{9}{10} - \frac{5}{6}$

   To subtract, find a common denominator for $10$ and $6$:
   Least common multiple (LCM) = $30$.

   Convert the fractions: $\frac{9}{10} = \frac{27}{30}, \quad \frac{5}{6} = \frac{25}{30}$

   Subtract: $\frac{27}{30} - \frac{25}{30} = \frac{2}{30} = \frac{1}{15}$

   Remaining ribbon = $\frac{1}{15}$ meters.

2. Step 2: Find ribbon used for 1 bow
   The remaining ribbon is used to make 3 bows.
   Ribbon per bow: $\text{Ribbon per bow} = \frac{\text{Remaining ribbon}}{\text{Number of bows}} = \frac{\frac{1}{15}}{3}$

   Divide $\frac{1}{15}$ by $3$ (or multiply by $\frac{1}{3}$): $\frac{1}{15} \times \frac{1}{3} = \frac{1}{45}$

   Ribbon used for 1 bow = $\frac{1}{45}$ meters.

Final Answer:

The ribbon used for 1 bow is $\frac{1}{45}$ meters.

Would you like a detailed breakdown of any specific step?
Here are 5 related questions to explore further:

1. How do you calculate the least common multiple (LCM) of two numbers?
2. What are the steps to simplify fractions like $\frac{2}{30}$ to $\frac{1}{15}$?
3. How can you divide fractions like $\frac{1}{15} \div 3$?
4. How is subtraction of fractions applied in everyday contexts?
5. Why is finding common denominators essential in fraction operations?

Tip: When working with fractions, always check for simplification to make results clearer.