Math Problem Statement

Find the Fourier series coefficients for the signal x(t) = 3 + 8 cos^2(5πt) + 6 sin(15πt).

Solution

The problem asks to find the Fourier series coefficients for the signal:

x(t)=3+8cos(5πt)+6sin(15πt)x(t) = 3 + 8 \cos(5\pi t) + 6 \sin(15\pi t)

To determine the Fourier series coefficients, we need to express the signal in the form:

x(t)=a0+n=1(ancos(nω0t)+bnsin(nω0t))x(t) = a_0 + \sum_{n=1}^{\infty} \left( a_n \cos(n\omega_0 t) + b_n \sin(n\omega_0 t) \right)

Where:

  • a0a_0 is the average (or DC) term,
  • ana_n and bnb_n are the cosine and sine Fourier coefficients respectively,
  • ω0\omega_0 is the fundamental angular frequency, which is related to the period of the signal.

Let's break down the signal:

  1. The constant term 33 contributes to a0a_0.
  2. The cosine term 8cos(5πt)8 \cos(5\pi t) contributes to the ana_n coefficient for n=5n = 5.
  3. The sine term 6sin(15πt)6 \sin(15\pi t) contributes to the bnb_n coefficient for n=15n = 15.

Next, we will compute the Fourier series coefficients.

Steps:

  1. DC coefficient (a0a_0): It is simply the constant term: a0=3a_0 = 3

  2. Cosine coefficients (ana_n): The general form of the coefficient ana_n is given by: an=2T0Tx(t)cos(nω0t)dta_n = \frac{2}{T} \int_{0}^{T} x(t) \cos(n\omega_0 t) dt In the case of this signal, we already see that for the term 8cos(5πt)8 \cos(5\pi t), we will get a non-zero ana_n only for n=5n = 5. Hence: a_5 = 8 \quad \text{(from the cosine term with frequency 5\pi)} For all other nn, an=0a_n = 0.

  3. Sine coefficients (bnb_n): The general form of the coefficient bnb_n is given by: bn=2T0Tx(t)sin(nω0t)dtb_n = \frac{2}{T} \int_{0}^{T} x(t) \sin(n\omega_0 t) dt In this case, the term 6sin(15πt)6 \sin(15\pi t) contributes a non-zero value only for n=15n = 15: b_{15} = 6 \quad \text{(from the sine term with frequency 15\pi)} For all other nn, bn=0b_n = 0.

Conclusion:

The Fourier series coefficients for the given signal are:

  • a0=3a_0 = 3,
  • a5=8a_5 = 8,
  • b15=6b_{15} = 6,
  • All other an=0a_n = 0 and bn=0b_n = 0 for n5,15n \neq 5, 15.

Let me know if you need further explanation or a detailed breakdown of any steps!


Here are some related questions you may find helpful:

  1. How do I compute the fundamental frequency for a periodic signal?
  2. What does it mean when Fourier coefficients are zero for certain frequencies?
  3. How can the Fourier series be used in signal processing applications?
  4. What is the significance of the DC term in the Fourier series?
  5. How do I handle complex exponentials in Fourier series analysis?

Tip: Always ensure that the frequency components in the signal are clearly identified before starting your Fourier analysis!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Fourier series
Trigonometric identities
Signal processing

Formulas

x(t) = a_0 + Σ [a_n cos(nω_0 t) + b_n sin(nω_0 t)]
a_0 = Average value of the signal
a_n = 2/T ∫ x(t) cos(nω_0 t) dt
b_n = 2/T ∫ x(t) sin(nω_0 t) dt

Theorems

Fourier series expansion theorem

Suitable Grade Level

University level (Electrical Engineering or Mathematics)