Math Problem Statement

Compute the force P to cause impending motion of block B to the left and to the right. Determine if a force P = 50 N or P = 150 N will cause motion, and if so, which block will move.

Solution

The problem involves calculating the force PP needed to cause impeding motion of block BB to the left and right under static friction conditions. Here's a breakdown of the provided information and how to approach the solution:

Given:

  • Weight of Block A=200NA = 200 \, \text{N}
  • Weight of Block B=100NB = 100 \, \text{N}
  • Coefficient of static friction, μs=0.20\mu_s = 0.20

Objective:

  1. Compute the force PP to cause impending motion of block BB to the left.
  2. Compute the force PP to cause impending motion of block BB to the right.
  3. Determine if a force P=50NP = 50 \, \text{N} applied to the left will cause motion, and if so, which block moves.
  4. Determine if a force P=150NP = 150 \, \text{N} applied to the left will cause motion, and if so, which block moves.

Solution Steps:

  1. Free Body Diagram Analysis:

    • Consider the forces acting on each block separately.

    • For Block AA on the inclined surface:

      • Normal force: NA=WA=200NN_A = W_A = 200 \, \text{N}
      • Friction force: fA=μs×NA=0.20×200=40Nf_A = \mu_s \times N_A = 0.20 \times 200 = 40 \, \text{N}
    • For Block BB:

      • Normal force: NB=WB=100NN_B = W_B = 100 \, \text{N}
      • Friction force: fB=μs×NB=0.20×100=20Nf_B = \mu_s \times N_B = 0.20 \times 100 = 20 \, \text{N}
  2. Calculating Force PP for Block BB Moving Left:

    • The force PP needs to overcome the static friction force on Block AA and also initiate movement for Block BB.
    • Total friction to overcome: Ffriction, total=fA+fB=40+20=60NF_{\text{friction, total}} = f_A + f_B = 40 + 20 = 60 \, \text{N}
    • Therefore, P=60NP = 60 \, \text{N} is needed to cause block BB to move left.
  3. Calculating Force PP for Block BB Moving Right:

    • Similarly, for block BB to move right, the force PP must again overcome the total friction force: P=60NP = 60 \, \text{N}
  4. Analysis for P=50NP = 50 \, \text{N}:

    • Since P=50N<60NP = 50 \, \text{N} < 60 \, \text{N}, the applied force is not sufficient to overcome the total friction. No motion will occur.
  5. Analysis for P=150NP = 150 \, \text{N}:

    • Since P=150N>60NP = 150 \, \text{N} > 60 \, \text{N}, the applied force is more than enough to overcome the total friction. Block BB will move to the left.

If you would like a more detailed breakdown of any of these steps or have specific questions, let me know!

Further Related Questions:

  1. What would be the force required if the coefficient of static friction were different?
  2. How would the result change if Block AA were on a different inclined angle?
  3. What happens if there is kinetic friction involved after the blocks start moving?
  4. How to calculate the acceleration of the blocks once they start moving?
  5. How does the force of PP change if Block BB is heavier than Block AA?

Tip:

Always remember to break the problem into smaller steps and analyze each block or component separately using free-body diagrams. This helps in clearly visualizing all forces involved.

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Math Problem Analysis

Mathematical Concepts

Statics
Friction
Force Analysis

Formulas

Friction force: f = μ_s * N
Total friction: F_friction_total = f_A + f_B

Theorems

Static friction threshold

Suitable Grade Level

Grades 11-12