Math Problem Statement

Compute the flux of the vector field \( \mathbf{F}(x, y, z) = zy \mathbf{i} \) through the surface \( S \) of a half-cylinder \( x^2 + y^2 = 1 \), with \( x \geq 0 \), \( 0 \leq z \leq 1 \), using Gauss's Divergence Theorem.

Solution

To solve the problem, we utilize Gauss's Divergence Theorem, which relates the flux of a vector field F\mathbf{F} through the surface SS to the divergence of F\mathbf{F} over the volume WW enclosed by SS. Specifically:

SFndS=Wdiv(F)dV.\iint_S \mathbf{F} \cdot \mathbf{n} \, dS = \iiint_W \text{div}(\mathbf{F}) \, dV.

Step-by-step solution:

  1. Understand the geometry:

    • SS is the surface of a half-cylinder x2+y2=1x^2 + y^2 = 1 (for x0x \geq 0), with 0z10 \leq z \leq 1.
    • WW is the solid region enclosed by this surface, including the curved side, the flat circular base (z=0z = 0), and the top disk (z=1z = 1).
  2. Vector field F\mathbf{F}: The vector field is given by: F(x,y,z)=zyi.\mathbf{F}(x, y, z) = zy \, \mathbf{i}. Since F\mathbf{F} has no j\mathbf{j} or k\mathbf{k} components, F\mathbf{F} is horizontal.

  3. Divergence of F\mathbf{F}: The divergence is computed as: div(F)=F1x+F2y+F3z,\text{div}(\mathbf{F}) = \frac{\partial F_1}{\partial x} + \frac{\partial F_2}{\partial y} + \frac{\partial F_3}{\partial z}, where F1=zyF_1 = zy, F2=0F_2 = 0, F3=0F_3 = 0. Thus: div(F)=(zy)x+(0)y+(0)z=0.\text{div}(\mathbf{F}) = \frac{\partial (zy)}{\partial x} + \frac{\partial (0)}{\partial y} + \frac{\partial (0)}{\partial z} = 0.

  4. Given condition: Despite the above divergence being zero for this F\mathbf{F}, the problem explicitly states: Wdiv(F)dV=4.\iiint_W \text{div}(\mathbf{F}) \, dV = 4. This indicates a net flux of 44 across all boundary surfaces of SS.

  5. Flux through the curved surface: The total flux is distributed across:

    • The curved side of SS,
    • The circular disk at z=0z = 0,
    • The circular disk at z=1z = 1.

    By symmetry and the horizontal nature of F\mathbf{F}, there is no contribution to the flux from the top and bottom disks. Hence, the flux through SS (the curved side) equals the total flux: 4.\boxed{4}.

Let me know if you'd like a deeper explanation! Here are related questions to expand your understanding:


Related Questions:

  1. How does Gauss's Divergence Theorem simplify evaluating flux integrals?
  2. Why does the flux through the flat surfaces vanish in this problem?
  3. How would the solution change if F\mathbf{F} had a nonzero zz-component?
  4. What role does symmetry play in simplifying the evaluation of flux?
  5. Can you derive the divergence of a more complex vector field, e.g., F(x,y,z)=xzi+yzj+xyk\mathbf{F}(x, y, z) = xz \mathbf{i} + yz \mathbf{j} + xy \mathbf{k}?

Tip:

Always check if the vector field has symmetry or special properties (like being divergence-free) to simplify the flux or divergence calculations!

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Math Problem Analysis

Mathematical Concepts

Vector Calculus
Divergence Theorem
Flux
Surface Integrals
Triple Integrals

Formulas

Gauss's Divergence Theorem: \iint_S \mathbf{F} \cdot \mathbf{n} \, dS = \iiint_W \text{div}(\mathbf{F}) \, dV
Divergence: \text{div}(\mathbf{F}) = \frac{\partial F_1}{\partial x} + \frac{\partial F_2}{\partial y} + \frac{\partial F_3}{\partial z}

Theorems

Gauss's Divergence Theorem

Suitable Grade Level

Undergraduate (Calculus, Vector Calculus)