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The problem involves mixing two types of flower seeds to create a 20-ounce mixture at a specific price. Let’s break down the situation mathematically.

### Known information:
- **Wild cosmo seeds** cost $9.60 per ounce.
- **Wild aster seeds** cost $11.80 per ounce.
- The mixture weighs **20 ounces** and costs **$10.15 per ounce**.

### Define Variables:
Let:
- $ x $ be the amount (in ounces) of wild cosmo seeds.
- $ 20 - x $ be the amount (in ounces) of wild aster seeds.

### Set up the equation:
We know the total cost of the mixture is the sum of the costs of both seeds:

\[
9.60x + 11.80(20 - x) = 10.15 \times 20
\]

Now, I will solve this equation to find the value of $ x $.The solution to the equation is $ x = 15 $. This means that **15 ounces** of wild cosmo seeds were used in the mixture.

Since the total weight of the mixture is 20 ounces, the amount of wild aster seeds used is:

\[
20 - 15 = 5 \text{ ounces}.
\]

### Summary:
- **Wild cosmo seeds**: 15 ounces
- **Wild aster seeds**: 5 ounces

Would you like further details, or do you have any questions?

Here are 5 related questions to deepen your understanding:
1. How would the equation change if the price of wild cosmo seeds increased?
2. What if the target price of the mixture was different, say $9.50 per ounce?
3. Can you generalize the formula for any mixture where two items are combined?
4. How would you solve the problem if the total weight was 30 ounces?
5. How does the relative price difference between the two types of seeds affect the amounts used?

**Tip:** For mixture problems, setting up equations based on total price and quantity is key to solving them efficiently.

A two different types of flower seeds are combined to make a special wild flower mix. If the wild cosmo seeds cost $9.60 per ounce and the wild aster seeds cost $11.80 per ounce, how many pounds of each were used to make a 20-ounce mixture that costs $10.15 per ounce?

Learn how to solve a linear equation mixture problem where two types of flower seeds are combined to form a 20-ounce mix costing $10.15 per ounce. This problem involves algebraic concepts and solving linear equations. Suitable for students in Grades 9-11.

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