Math Problem Statement

A can contains a mixture of two liquids A and B is the ratio 7 : 5 . When 9 litres of mixture are drawn off and the can is filled with B , the ratio of A and B becomes 7 : 9 . How many litres of liquid A was contained by the can initially? 20 21 10 25

Solution

Let's solve this problem step by step.

Step 1: Define Variables

Let the initial quantity of liquid AA in the can be 7x7x liters, and the initial quantity of liquid BB in the can be 5x5x liters. Thus, the total volume of the mixture is 7x+5x=12x7x + 5x = 12x liters.

Step 2: Mixture After Drawing Off 9 Liters

When 9 liters of the mixture is drawn off, the ratio of liquid AA and BB remains the same (7:5). So, the amount of liquid AA drawn off is: Amount of A drawn off=712×9=6312=5.25 liters\text{Amount of A drawn off} = \frac{7}{12} \times 9 = \frac{63}{12} = 5.25 \text{ liters} And the amount of liquid BB drawn off is: Amount of B drawn off=512×9=4512=3.75 liters\text{Amount of B drawn off} = \frac{5}{12} \times 9 = \frac{45}{12} = 3.75 \text{ liters}

After removing 9 liters, the remaining amount of liquid AA is: 7x5.25 liters7x - 5.25 \text{ liters} And the remaining amount of liquid BB is: 5x3.75 liters5x - 3.75 \text{ liters}

Step 3: Refilling with Liquid B

The can is refilled with 9 liters of liquid BB, so the new quantity of liquid BB is: (5x3.75)+9=5x+5.25 liters(5x - 3.75) + 9 = 5x + 5.25 \text{ liters}

Step 4: New Ratio After Refilling

The new ratio of liquid AA to liquid BB is given as 7:97:9. Thus: 7x5.255x+5.25=79\frac{7x - 5.25}{5x + 5.25} = \frac{7}{9}

Step 5: Solve the Equation

Now, cross-multiply to solve for xx: 9(7x5.25)=7(5x+5.25)9(7x - 5.25) = 7(5x + 5.25) Expanding both sides: 63x47.25=35x+36.7563x - 47.25 = 35x + 36.75 Simplifying: 63x35x=36.75+47.2563x - 35x = 36.75 + 47.25 28x=8428x = 84 x=3x = 3

Step 6: Initial Amount of Liquid A

The initial amount of liquid AA was 7x7x liters: 7x=7×3=21 liters7x = 7 \times 3 = 21 \text{ liters}

Final Answer

The initial amount of liquid AA in the can was 21 liters.

Would you like more details or have any questions?


Related Questions:

  1. How would the solution change if the ratio after refilling became 8:9 instead of 7:9?
  2. What would happen if 12 liters were drawn off instead of 9 liters?
  3. Can this problem be solved using a different method, such as algebraic substitution?
  4. How would the initial quantities change if the ratio of A to B was initially 5:7 instead?
  5. What is the effect of adding more than 9 liters of liquid B to the can after drawing off the mixture?
  6. How could you verify the solution through a different logical approach?
  7. What if the total volume of the can was limited, say to 15 liters? How would that affect the problem?
  8. How would the problem change if liquid A evaporated at a constant rate during the process?

Tip:

When solving ratio problems, carefully track the quantities before and after any changes to ensure accuracy in your final answer.

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Math Problem Analysis

Mathematical Concepts

Ratio and proportion
Algebraic equations
Mixture problems

Formulas

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Theorems

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Suitable Grade Level

Grades 9-12