Math Problem Statement

Calculate the flow rate in pipe 2 using the Colebrook–White equation for a three-reservoir system driven by gravity, assuming turbulent flow and wide reservoirs.

Solution

To solve this problem, we need to calculate the flow rate in pipe 2 (Q2Q_2) for a system driven by gravity with turbulent flow. Here’s the breakdown of the approach:

Key Steps:

  1. Determine the Head Loss in Pipes (Using Energy Balance): Since gravity drives the flow between reservoirs, there’s a potential energy difference based on elevation heights (z1,z2,z3z_1, z_2, z_3). The head loss due to friction must equal the energy difference between reservoirs.

  2. Colebrook–White Equation for Friction Factor: To find the friction factor fdf_d in each pipe, we’ll use the Colebrook–White equation: 1fd=2log10(ϵ3.7D+2.51Refd)\frac{1}{\sqrt{f_d}} = -2 \log_{10} \left( \frac{\epsilon}{3.7D} + \frac{2.51}{\text{Re} \sqrt{f_d}} \right) This equation is implicit, meaning fdf_d needs to be solved iteratively, as it appears on both sides.

  3. Reynolds Number Calculation: For each pipe, calculate the Reynolds number Re=ρVDμ\text{Re} = \frac{\rho V D}{\mu} where VV is the flow velocity, DD is the diameter, ρ\rho is the fluid density, and μ\mu is the dynamic viscosity. Assuming the fluid properties are known, this will help us in the iterative solution for fdf_d.

  4. Flow Balance at Junction AA: Since we have three pipes connected at junction AA, the sum of inflows must equal the sum of outflows. If we denote flows in pipes as Q1,Q2,Q3Q_1, Q_2, Q_3, then: Q1+Q3=Q2Q_1 + Q_3 = Q_2 Here, we will determine flow directions based on positive or negative flow rates relative to the junction.

  5. Iterative Solution for Q2Q_2: With the friction factors calculated for each pipe, use the energy and continuity equations to solve for Q2Q_2 iteratively until it converges to a stable value.

Given Parameters:

  • Lengths L1=125m,L2=25m,L3=125mL_1 = 125 \, \text{m}, L_2 = 25 \, \text{m}, L_3 = 125 \, \text{m}
  • Elevations z1=1275m,z2=1000m,z3=100mz_1 = 1275 \, \text{m}, z_2 = 1000 \, \text{m}, z_3 = 100 \, \text{m}
  • Diameters D1=0.2m,D2=0.2m,D3=0.15mD_1 = 0.2 \, \text{m}, D_2 = 0.2 \, \text{m}, D_3 = 0.15 \, \text{m}
  • Roughness ϵ1=1mm,ϵ2=0.25mm,ϵ3=0.5mm\epsilon_1 = 1 \, \text{mm}, \epsilon_2 = 0.25 \, \text{mm}, \epsilon_3 = 0.5 \, \text{mm}

Next Steps:

  1. Assume an initial guess for fdf_d and Q2Q_2 to start the iteration.
  2. Use the Colebrook–White equation to refine the friction factors based on the guessed flow rate.
  3. Apply the energy balance and continuity conditions to update the flow rates.
  4. Iterate until convergence for Q2Q_2 to three significant figures.

Would you like a more detailed walkthrough of any specific part of this process, or have any questions?

Here are some further questions related to the topic:

  1. How would you use the Moody chart if the Colebrook–White equation wasn't provided?
  2. What are the implications of assuming all reservoirs are "wide" in this scenario?
  3. How does the choice of initial guess affect the convergence of iterative methods?
  4. What are some common methods to numerically solve implicit equations like the Colebrook–White equation?
  5. Why do we ignore minor losses in this analysis, and how would including them affect the result?

Tip: When iterating to find the friction factor, use the previous iteration's value as the starting point for the next. This often speeds up convergence.

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Math Problem Analysis

Mathematical Concepts

Fluid Mechanics
Hydraulic Systems
Colebrook–White Equation
Energy Balance

Formulas

Colebrook–White Equation: 1/sqrt(f_d) = -2 log10((ε/(3.7D)) + (2.51/(Re sqrt(f_d))))
Reynolds Number: Re = (ρVD)/μ
Flow Balance: Q1 + Q3 = Q2

Theorems

Energy Conservation in Fluid Flow
Continuity Equation

Suitable Grade Level

Undergraduate Engineering