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The problem in the image asks to calculate the flow rate given a velocity of 2880 m/h, and the required units are:

- liters per hour (l/h)
- liters per second (l/s)
- cubic meters per hour (m³/h)
- cubic meters per second (m³/s)

To convert the velocity (flow speed) into flow rate, we need to know the cross-sectional area of the flow (if it's a pipe, for example, we need the pipe's diameter or area). Without that information, I can explain the general process of converting between units:

1. **To calculate the flow in liters per hour (l/h):**
   - Multiply the flow velocity in meters per hour (m/h) by the cross-sectional area in square meters.
   - \( 1 \, \text{m³} = 1000 \, \text{liters} \)

2. **To calculate the flow in liters per second (l/s):**
   - Convert m/h to m/s by dividing by 3600 (since \( 1 \, \text{hour} = 3600 \, \text{seconds} \)).
   - Multiply the result by 1000 to convert cubic meters to liters.

3. **To calculate the flow in cubic meters per hour (m³/h):**
   - If you already have the flow rate in m³, the conversion is straightforward since the velocity is given in meters per hour.

4. **To calculate the flow in cubic meters per second (m³/s):**
   - Convert m/h to m/s and keep the result in cubic meters.

However, to proceed further, the missing piece of information (such as the cross-sectional area or diameter) is required. Could you provide more details about the setup or area of flow?

Do you need any specific conversions, or should we wait for more information? Here are 5 relative questions that could guide you further:

1. Is the flow happening through a pipe or an open channel?
2. What is the cross-sectional area of the flow?
3. Are there any assumptions you would like to make regarding the shape of the cross-section (e.g., circular, rectangular)?
4. Would you like the detailed formulas for these unit conversions?
5. Do you need explanations on unit conversions between liters and cubic meters?

**Tip:** Always ensure that the cross-sectional area is in square meters (m²) for consistency with the given velocity in meters per hour.

On donne la vitesse d'écoulement de 2880 m/h. On demande de calculer : Le débit en l/h ; l/s ; m³/h ; m³/s.

This problem involves calculating the flow rate in liters per hour (l/h), liters per second (l/s), cubic meters per hour (m³/h), and cubic meters per second (m³/s) given a velocity of 2880 m/h. Key concepts include unit conversion and fluid dynamics. Suitable for advanced high school or college-level physics students.

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