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### Problem b)

You are given the flow velocity: \( v = 0.8 \, \text{m/s} \)

You are asked to calculate the flow rate in:

1. \( \text{l/h} \)
2. \( \text{l/s} \)
3. \( \text{m}^3/\text{h} \)
4. \( \text{m}^3/\text{s} \)

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### Formula:

Flow rate \( Q \) is given by:

\[
Q = v \times A
\]

Where:
- \( Q \) is the flow rate
- \( v \) is the flow velocity \( 0.8 \, \text{m/s} \)
- \( A \) is the cross-sectional area of the pipe (in m²), which can be calculated if we know the diameter of the pipe.

From the notes, I can see some values for the diameter: \( D = 1.56056 \, \text{m} \).

The cross-sectional area \( A \) is calculated using the formula for the area of a circle:

\[
A = \pi \times \left( \frac{D}{2} \right)^2
\]

Substituting \( D = 1.56056 \, \text{m} \) into the formula will give us the area, and we can use that to find the flow rate.

Would you like me to calculate these values for you, or do you have additional information to clarify before we proceed?

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### Questions:
1. How is the flow rate affected by changes in velocity?
2. What is the significance of converting between \( \text{l/h} \), \( \text{m}^3/\text{h} \), and \( \text{m}^3/\text{s} \)?
3. Can you explain how the cross-sectional area influences flow rate?
4. What would happen to the flow rate if the pipe's diameter was doubled?
5. Why are both liters and cubic meters used as units of flow rate?

### Tip:
Always ensure that the units of measurement are consistent when using formulas involving flow rates, areas, and velocities.

On donne la vitesse d'écoulement de 0,8 m/s. On demande de calculer : le débit en l/h ; l/s ; m3/h ; m3/s.

Learn how to calculate the flow rate in liters per hour, liters per second, cubic meters per hour, and cubic meters per second from a given velocity of 0.8 m/s. This problem covers fluid dynamics and unit conversion, suitable for high school students.

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