Math Problem Statement

Use simple fixed point iteration to locate the root of f(x)=-9x^2+1.7x+2.5 with initial value of x=5

Solution

To solve the equation f(x)=9x2+1.7x+2.5=0f(x) = -9x^2 + 1.7x + 2.5 = 0 using simple fixed-point iteration, we need to rewrite the equation in the form x=g(x)x = g(x). Let's isolate xx to set up the iteration formula.

We can rearrange the equation as follows:

x=g(x)=1.7x+2.59xx = g(x) = \frac{1.7x + 2.5}{9x}

For simplicity, we'll now start the fixed-point iteration method:

Steps for Fixed-Point Iteration:

  1. Choose an initial guess for x0x_0. Given x0=5x_0 = 5.
  2. Use the function g(x)g(x) to calculate the next xx value: xn+1=g(xn)x_{n+1} = g(x_n)
  3. Repeat the process until the values converge.

Let's compute the first few iterations manually:

Iteration 1:

Using x0=5x_0 = 5: x1=g(x0)=1.7(5)+2.59(5)=8.5+2.545=11450.2444x_1 = g(x_0) = \frac{1.7(5) + 2.5}{9(5)} = \frac{8.5 + 2.5}{45} = \frac{11}{45} \approx 0.2444

Iteration 2:

Now, using x1=0.2444x_1 = 0.2444: x2=g(x1)=1.7(0.2444)+2.59(0.2444)=0.41548+2.52.19961.3242x_2 = g(x_1) = \frac{1.7(0.2444) + 2.5}{9(0.2444)} = \frac{0.41548 + 2.5}{2.1996} \approx 1.3242

Iteration 3:

Using x2=1.3242x_2 = 1.3242: x3=g(x2)=1.7(1.3242)+2.59(1.3242)=2.25114+2.511.9180.3779x_3 = g(x_2) = \frac{1.7(1.3242) + 2.5}{9(1.3242)} = \frac{2.25114 + 2.5}{11.918} \approx 0.3779

Iteration 4:

Using x3=0.3779x_3 = 0.3779: x4=g(x3)=1.7(0.3779)+2.59(0.3779)=0.64243+2.53.40110.921x_4 = g(x_3) = \frac{1.7(0.3779) + 2.5}{9(0.3779)} = \frac{0.64243 + 2.5}{3.4011} \approx 0.921

The process will continue until convergence (when xn+1xn|x_{n+1} - x_n| is sufficiently small).

Would you like me to continue more iterations, or would you like a detailed explanation of each step?

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Math Problem Analysis

Mathematical Concepts

Fixed Point Iteration
Root Finding
Quadratic Equations

Formulas

f(x) = -9x^2 + 1.7x + 2.5
g(x) = (1.7x + 2.5) / (9x)

Theorems

Fixed Point Theorem

Suitable Grade Level

Undergraduate Level