To compute the five-number summary of the given data, we need the following values:

1. Minimum (Min): The smallest value in the dataset.
2. First Quartile (Q1): The median of the lower half of the dataset (25th percentile).
3. Median (Q2): The middle value when the data is ordered.
4. Third Quartile (Q3): The median of the upper half of the dataset (75th percentile).
5. Maximum (Max): The largest value in the dataset.

Let’s first organize the data in ascending order and then compute these values.

Raw data:

0.57, 0.39, 0, 2.98, 0.34, 2.59, 2.42, 2.71, 0.32, 2.88, 0, 2.84, 3.06, 0.31, 1.72, 3.54, 1.72, 0.98, 1.33, 2.96, 0, 0.33, 0, 0.41, 1.99, 0.13, 1.5, 0.15

Step 1: Sort the data in ascending order:

0, 0, 0, 0, 0.13, 0.15, 0.31, 0.32, 0.33, 0.34, 0.39, 0.41, 0.57, 0.98, 1.33, 1.5, 1.72, 1.72, 1.99, 2.42, 2.59, 2.71, 2.84, 2.88, 2.96, 2.98, 3.06, 3.54

Step 2: Identify the five-number summary:

1. Minimum (Min): The smallest number is 0.
2. Maximum (Max): The largest number is 3.54.
3. Median (Q2): The middle value in this ordered list of 28 numbers. Since there are 28 numbers (an even number), we average the 14th and 15th values.
   • 14th value: 0.98
   • 15th value: 1.33
   • Median $Q2$ = $\frac{0.98 + 1.33}{2} = 1.16$
4. First Quartile (Q1): The median of the first half of the data (the first 14 values). This is the median of the numbers from 0 to 0.98.
   • 7th value: 0.31
   • 8th value: 0.32
   • First Quartile $Q1$ = $\frac{0.31 + 0.32}{2} = 0.315$
5. Third Quartile (Q3): The median of the second half of the data (the numbers from 1.5 to 3.54). This is the median of the numbers from 1.5 to 3.54.
   • 7th value in this half (21st overall): 2.42
   • 8th value in this half (22nd overall): 2.59
   • Third Quartile $Q3$ = $\frac{2.42 + 2.59}{2} = 2.505$

Summary:

• Minimum (Min): 0
• First Quartile (Q1): 0.315
• Median (Q2): 1.16
• Third Quartile (Q3): 2.505
• Maximum (Max): 3.54

Thus, the five-number summary is:

• 0, 0.32, 1.16, 2.51, 3.54.

Would you like further explanations or help with another part of the problem?