Math Problem Statement

The following data represent the dividend yields​ (in percent) of a random sample of 28 publicly traded stocks. Complete parts ​(a) to​ (c). 2.892.89 0.080.08 1.561.56 0.180.18 0.410.41 2.622.62 0.160.16 1.661.66 0.410.41 1.911.91 00 00 2.892.89 0.380.38 2.512.51 3.683.68 2.382.38 0.480.48 1.541.54 3.183.18 00 0.40.4 00 1.281.28 0.980.98 0.360.36 2.752.75 2.882.88

Question content area bottom Part 1 ​(a) Compute the​ five-number summary. The​ five-number summary is enter your response here​, enter your response here​, enter your response here​, enter your response here​, enter your response here. ​(Round to two decimal places as needed. Use ascending​ order.)

Solution

To compute the five-number summary, we need to calculate the following values from the dataset:

  1. Minimum: The smallest value in the dataset.
  2. First quartile (Q1): The median of the lower half of the data (excluding the overall median if the number of data points is odd).
  3. Median (Q2): The middle value of the dataset.
  4. Third quartile (Q3): The median of the upper half of the data.
  5. Maximum: The largest value in the dataset.

Steps:

  1. Sort the data in ascending order: 0,0,0,0,0.08,0.16,0.18,0.36,0.38,0.4,0.41,0.41,0.48,0.98,1.28,1.54,1.56,1.66,1.91,2.38,2.51,2.62,2.75,2.88,2.89,2.89,3.18,3.680, 0, 0, 0, 0.08, 0.16, 0.18, 0.36, 0.38, 0.4, 0.41, 0.41, 0.48, 0.98, 1.28, 1.54, 1.56, 1.66, 1.91, 2.38, 2.51, 2.62, 2.75, 2.88, 2.89, 2.89, 3.18, 3.68 The dataset has 28 values.

  2. Minimum: The smallest value is 00.

  3. First Quartile (Q1): To find Q1, locate the median of the lower half (the first 14 values): 0,0,0,0,0.08,0.16,0.18,0.36,0.38,0.4,0.41,0.41,0.48,0.980, 0, 0, 0, 0.08, 0.16, 0.18, 0.36, 0.38, 0.4, 0.41, 0.41, 0.48, 0.98 The median of these 14 values is the average of the 7th and 8th values: Q1=0.18+0.362=0.27\text{Q1} = \frac{0.18 + 0.36}{2} = 0.27

  4. Median (Q2): The overall median is the average of the 14th and 15th values: Q2=0.98+1.282=1.13\text{Q2} = \frac{0.98 + 1.28}{2} = 1.13

  5. Third Quartile (Q3): To find Q3, locate the median of the upper half (the last 14 values): 1.28,1.54,1.56,1.66,1.91,2.38,2.51,2.62,2.75,2.88,2.89,2.89,3.18,3.681.28, 1.54, 1.56, 1.66, 1.91, 2.38, 2.51, 2.62, 2.75, 2.88, 2.89, 2.89, 3.18, 3.68 The median of these 14 values is the average of the 7th and 8th values: Q3=2.51+2.622=2.57\text{Q3} = \frac{2.51 + 2.62}{2} = 2.57

  6. Maximum: The largest value is 3.683.68.

The five-number summary is:

0,0.27,1.13,2.57,3.68\boxed{0, 0.27, 1.13, 2.57, 3.68}

Would you like details on how to calculate these, or do you have other questions?


Here are 5 questions related to this:

  1. How can the five-number summary help describe the distribution of data?
  2. What is the significance of the interquartile range (IQR), and how would you compute it from the five-number summary?
  3. How can you identify outliers using the five-number summary?
  4. What is the relationship between the median and the mean in a skewed dataset?
  5. How do boxplots visually represent the five-number summary?

Tip: To better understand the spread of data, focus on how far the quartiles are from each other—this helps measure variability.

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Math Problem Analysis

Mathematical Concepts

Descriptive Statistics
Five-Number Summary
Quartiles

Formulas

Minimum: The smallest value in the data set
Q1: Median of the lower half of the data
Median (Q2): Middle value of the data
Q3: Median of the upper half of the data
Maximum: The largest value in the data set

Theorems

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Suitable Grade Level

Grades 9-12