Math Problem Statement
用这种方法拟合一次函数是否可行,是否存在改进或者优化的地方请用中文给出?clist为cv2读入的图像的5个坐标点。 if len(clist) > 0: clist_end= clist try: k = float(-clist_end[-2][1] + clist_end[-1][1]) / (clist_end[-2][0] - clist_end[-1][0]) # 斜率k b = -clist_end[-1][1] - k * clist_end[-1][0] # 偏移量b print('k', k) print('b', b) for i in range(len(clist)): if clist_end[i][1] < 0: clist_end[i][1] *= -1
绘制修正箭头和直线
cv2.line(img_start, (clist_end[i][0] - 10, clist_end[i][1] + 8), (clist_end[i][0], clist_end[i][1]), (255, 0, 0), 2) # 左边箭头 cv2.line(img_start, (clist_end[i][0] + 10, clist_end[i][1] + 8), (clist_end[i][0], clist_end[i][1]), (255, 0, 0), 2) # 右边箭头 cv2.line(img_start, (clist_end[i][0], clist_end[i][1]), (clist_end[i][0], clist_end[i][1] + 18), (255, 0, 0), 3) # 下边直线 except: k = 1.00002 print('k', k) clist_end = clist for i in range(len(clist)):
绘制修正箭头和直线
cv2.line(img_start, (clist_end[i][0] - 10, clist_end[i][1] + 8), (clist_end[i][0], clist_end[i][1]), (255, 0, 0), 2) # 左边箭头 cv2.line(img_start, (clist_end[i][0] + 10, clist_end[i][1] + 8), (clist_end[i][0], clist_end[i][1]), (255, 0, 0), 2) # 右边箭头 cv2.line(img_start, (clist_end[i][0], clist_end[i][1]), (clist_end[i][0], clist_end[i][1] + 18), (255, 0, 0), 3) # 下边直线
Solution
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Linear Regression
Coordinate Geometry
Formulas
Linear equation: y = kx + b
Theorems
-
Suitable Grade Level
Advanced Mathematics
Related Recommendation
Calculate R-squared Values for Linear, Quadratic, and Exponential Regression Models
Deriving the Equation of a Plane from a 2D Line in the Image Coordinate System
Understanding Image Matching with SIFT and Homography Calculation
Find the Slope of a Dotted Line in an Image: Step-by-Step Solution
Calculate Regression Line Equation and Data Characteristics