The given sequence is defined as:

$a_n = 4n + 7$

To find the first three terms, substitute $n = 1$, $n = 2$, and $n = 3$ into the formula:

1. For $n = 1$: $a_1 = 4(1) + 7 = 4 + 7 = 11$

2. For $n = 2$: $a_2 = 4(2) + 7 = 8 + 7 = 15$

3. For $n = 3$: $a_3 = 4(3) + 7 = 12 + 7 = 19$

Thus, the first three terms of the sequence are: 11, 15, 19.

Would you like further explanation or have any questions?

Here are 5 related questions:

1. What would be the 5th term of the sequence?
2. How would you find the 100th term of this sequence?
3. What is the common difference in this arithmetic sequence?
4. Can you write the general formula for the nth term of this sequence in a different form?
5. How does changing the constant in the formula affect the sequence?

Tip: For arithmetic sequences, the difference between consecutive terms remains constant, known as the common difference.