Math Problem Statement

first and second order partial derivative of z=4x³y²

Solution

To find the first and second order partial derivatives of the function:

z=4x3y2z = 4x^3y^2

First Order Partial Derivatives

  1. Partial derivative with respect to xx:

    zx=x(4x3y2)\frac{\partial z}{\partial x} = \frac{\partial}{\partial x} (4x^3y^2)

    Using the power rule for differentiation on xx:

    zx=43x2y2=12x2y2\frac{\partial z}{\partial x} = 4 \cdot 3x^2 \cdot y^2 = 12x^2y^2

  2. Partial derivative with respect to yy:

    zy=y(4x3y2)\frac{\partial z}{\partial y} = \frac{\partial}{\partial y} (4x^3y^2)

    Using the power rule for differentiation on yy:

    zy=4x32y=8x3y\frac{\partial z}{\partial y} = 4x^3 \cdot 2y = 8x^3y

Second Order Partial Derivatives

  1. Second partial derivative with respect to xx:

    2zx2=x(12x2y2)\frac{\partial^2 z}{\partial x^2} = \frac{\partial}{\partial x} \left( 12x^2y^2 \right)

    Differentiating 12x2y212x^2y^2 with respect to xx:

    2zx2=122xy2=24xy2\frac{\partial^2 z}{\partial x^2} = 12 \cdot 2x \cdot y^2 = 24xy^2

  2. Second partial derivative with respect to yy:

    2zy2=y(8x3y)\frac{\partial^2 z}{\partial y^2} = \frac{\partial}{\partial y} \left( 8x^3y \right)

    Differentiating 8x3y8x^3y with respect to yy:

    2zy2=8x31=8x3\frac{\partial^2 z}{\partial y^2} = 8x^3 \cdot 1 = 8x^3

  3. Mixed partial derivative with respect to xx and yy:

    • First, x(zy)\frac{\partial}{\partial x} \left( \frac{\partial z}{\partial y} \right):

      2zxy=x(8x3y)\frac{\partial^2 z}{\partial x \partial y} = \frac{\partial}{\partial x} \left( 8x^3y \right)

      Differentiating 8x3y8x^3y with respect to xx:

      2zxy=83x2y=24x2y\frac{\partial^2 z}{\partial x \partial y} = 8 \cdot 3x^2 \cdot y = 24x^2y

    • Second, y(zx)\frac{\partial}{\partial y} \left( \frac{\partial z}{\partial x} \right):

      2zyx=y(12x2y2)\frac{\partial^2 z}{\partial y \partial x} = \frac{\partial}{\partial y} \left( 12x^2y^2 \right)

      Differentiating 12x2y212x^2y^2 with respect to yy:

      2zyx=12x22y=24x2y\frac{\partial^2 z}{\partial y \partial x} = 12x^2 \cdot 2y = 24x^2y

    Since mixed partial derivatives are equal, we have:

    2zxy=2zyx=24x2y\frac{\partial^2 z}{\partial x \partial y} = \frac{\partial^2 z}{\partial y \partial x} = 24x^2y

Summary of the Partial Derivatives

  • First Order:

    • zx=12x2y2\frac{\partial z}{\partial x} = 12x^2y^2
    • zy=8x3y\frac{\partial z}{\partial y} = 8x^3y
  • Second Order:

    • 2zx2=24xy2\frac{\partial^2 z}{\partial x^2} = 24xy^2
    • 2zy2=8x3\frac{\partial^2 z}{\partial y^2} = 8x^3
    • 2zxy=2zyx=24x2y\frac{\partial^2 z}{\partial x \partial y} = \frac{\partial^2 z}{\partial y \partial x} = 24x^2y

Would you like more details on any of these steps, or have further questions?

Related Questions:

  1. What are higher-order partial derivatives and their applications?
  2. How do we interpret mixed partial derivatives geometrically?
  3. Can we find the gradient and Hessian matrix of z=4x3y2z = 4x^3y^2?
  4. How do mixed partial derivatives relate to Clairaut’s theorem?
  5. What are some practical uses of partial derivatives in real-world problems?

Tip:

When dealing with partial derivatives, always check if mixed derivatives are equal; this verifies smoothness and continuity in most contexts.

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Math Problem Analysis

Mathematical Concepts

Calculus
Partial Derivatives
Second-Order Derivatives

Formulas

First-order partial derivative formulas: ∂z/∂x and ∂z/∂y
Second-order partial derivative formulas: ∂²z/∂x², ∂²z/∂y², ∂²z/∂x∂y

Theorems

Clairaut's Theorem on Equality of Mixed Partial Derivatives

Suitable Grade Level

Undergraduate Calculus