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The problem asks for the zero of a linear function \( f \) that passes through the point \( (1, -9) \) and has a slope of \( -3 \).

To find the zero of the function (where \( f(x) = 0 \)), we can follow these steps:

### 1. Write the equation of the line in slope-intercept form:
The slope-intercept form is:
\[
y = mx + b
\]
where \( m \) is the slope and \( b \) is the y-intercept. We're given the slope \( m = -3 \), and the point \( (1, -9) \) lies on the line. We can substitute these values into the equation to find \( b \).

\[
-9 = -3(1) + b
\]
\[
-9 = -3 + b
\]
\[
b = -6
\]

Thus, the equation of the line is:
\[
y = -3x - 6
\]

### 2. Find the zero of the function:
To find the zero of \( f \), we need to solve for \( x \) when \( y = 0 \):
\[
0 = -3x - 6
\]
\[
3x = -6
\]
\[
x = -2
\]

Thus, the zero of the function is \( x = -2 \).

### Answer:
The correct answer is \( \boxed{-2} \), which corresponds to option C.

Let me know if you would like more details or have further questions!

Here are five follow-up questions for further exploration:
1. What is the y-intercept of the line given the equation \( y = -3x - 6 \)?
2. How do we find the slope from two points on a line?
3. How would the graph of the equation \( y = -3x - 6 \) look?
4. What would the zero be if the slope was \( 2 \) instead of \( -3 \)?
5. How would the zero change if the y-intercept \( b \) was \( 0 \)?

**Tip:** The zero of a function is where the graph of the function crosses the x-axis.

Huey drew linear function f which passes through the point (1, -9) and has a slope of -3. What is the zero of f?

Learn how to find the zero of a linear function that passes through the point (1, -9) and has a slope of -3. This problem covers key algebraic concepts, including the slope-intercept form of a linear equation and solving for the x-intercept. Suitable for students in Grades 8-9.

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