To find the y-intercept of the function $g(x) = (x+1)(x-2)(x+5)$, we need to evaluate $g(0)$, since the y-intercept occurs where $x = 0$.

Let's substitute $x = 0$ into the equation:

$g(0) = (0+1)(0-2)(0+5)$ $g(0) = (1)(-2)(5)$ $g(0) = -10$

So, the y-intercept is $y = -10$. Therefore, the point of the y-intercept is $(0, -10)$.

Would you like more details on how this is derived, or do you have any other questions? Here are some related questions you might find useful:

1. How do you factor a cubic function like this one?
2. What are the roots of the equation $g(x) = 0$?
3. How can you graph a cubic function based on its factors?
4. How do you find the x-intercepts of a polynomial?
5. What is the general form of a cubic function?

Tip: To quickly find the y-intercept of any function, always set $x = 0$ and solve for $y$.