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Find the  x
-components of each of the three pulls.
Express your answers in newtons separated by commas.
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F985N,x;F788N,x;F411N,x
=

We are tasked with finding the **x-components** of three force vectors based on the image you've uploaded.

### Step-by-step breakdown:

1. **Forces**:
   - Force 1: \( 985 \, \text{N} \) at an angle of \( 31^\circ \) from the positive \( x \)-axis.
   - Force 2: \( 788 \, \text{N} \) at an angle of \( 32^\circ \) from the negative \( y \)-axis.
   - Force 3: \( 411 \, \text{N} \) at an angle of \( 53^\circ \) from the negative \( x \)-axis.

2. **Formulas to find the x-components**:
   - The x-component of a force is given by: 
     \[
     F_x = F \cdot \cos(\theta)
     \]
     where \( F \) is the magnitude of the force, and \( \theta \) is the angle relative to the positive or negative \( x \)-axis.

### Calculations:

1. **Force \( 985 \, \text{N} \) (at \( 31^\circ \))**:
   - This force is in the first quadrant, so the x-component is positive:
     \[
     F_{985N,x} = 985 \cdot \cos(31^\circ) \approx 985 \cdot 0.8572 \approx 843.34 \, \text{N}
     \]

2. **Force \( 788 \, \text{N} \) (at \( 32^\circ \) from the negative \( y \)-axis)**:
   - This force is in the second quadrant (negative x-component):
     \[
     F_{788N,x} = -788 \cdot \cos(32^\circ) \approx -788 \cdot 0.8480 \approx -668.62 \, \text{N}
     \]

3. **Force \( 411 \, \text{N} \) (at \( 53^\circ \) from the negative \( x \)-axis)**:
   - This force is in the third quadrant, meaning the x-component is negative:
     \[
     F_{411N,x} = -411 \cdot \cos(53^\circ) \approx -411 \cdot 0.6018 \approx -247.34 \, \text{N}
     \]

### Final answers:
\[
F_{985N,x} \approx 843.34 \, \text{N}, \quad F_{788N,x} \approx -668.62 \, \text{N}, \quad F_{411N,x} \approx -247.34 \, \text{N}
\]

Let me know if you want further details on the calculations or if you have any questions!

### Related questions:
1. How do we calculate the **y-components** of each of these forces?
2. What would be the net force in the **x-direction** if these were the only forces acting on the object?
3. How does the angle orientation affect whether the x-component is positive or negative?
4. Could we determine the resultant force vector by combining both the x and y components?
5. How would the forces change if they were acting on an inclined plane?

**Tip**: Remember that cosine gives the adjacent (x-component) of a right triangle, while sine gives the opposite (y-component).

Find the x-components of each of the three pulls. Express your answers in newtons separated by commas.

Learn how to find the x-components of three forces with given magnitudes and angles. The problem involves applying trigonometric formulas to break down each force into its x-component. Suitable for students in higher-level physics courses.

Math Problem Statement

F985N,x;F788N,x;F411N,x

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