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To find the component form of the vector \(\overrightarrow{KL}\), we need to calculate the difference in the x-coordinates and y-coordinates between points \(K\) and \(L\).

Given:
- \(K(5, -6)\)
- \(L(8, -6)\)

### Step 1: Calculate the x-component
The x-component of \(\overrightarrow{KL}\) is:
\[
x_2 - x_1 = 8 - 5 = 3
\]

### Step 2: Calculate the y-component
The y-component of \(\overrightarrow{KL}\) is:
\[
y_2 - y_1 = -6 - (-6) = 0
\]

### Result
The component form of \(\overrightarrow{KL}\) is:
\[
\langle 3, 0 \rangle
\]

Let me know if you'd like me to explain further or find the length of the vector!

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**Would you like the length calculation or any additional explanations?**

Here are related questions to deepen your understanding:
1. What is the formula for finding the component form of a vector in 2D?
2. How would the component form change if \(K\) and \(L\) were in different quadrants?
3. How do you calculate the magnitude (or length) of a vector given its components?
4. Can you extend the same approach to find the component form in 3D space?
5. Why does a vector with a component form \(\langle a, 0 \rangle\) lie along the x-axis?

**Tip:** The length (magnitude) of a vector \(\langle a, b \rangle\) can be found using \(\sqrt{a^2 + b^2}\).

Find the component form of the vector given the initial and terminating points. Then find the length of the vector.
K(5, -6), L(8, -6)

Learn how to find the component form and length of the vector between points K(5, -6) and L(8, -6). This example covers essential concepts in vector calculations, including component form and magnitude, ideal for Grades 9-10.

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