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The task requires the slope of a line passing through the points $(-2, -1)$ and $(0, 4)$. Let's calculate the slope and then answer the two questions:

Formula for slope:

$m = \frac{y_2 - y_1}{x_2 - x_1}$ Using the points $(-2, -1)$ and $(0, 4)$: $m = \frac{4 - (-1)}{0 - (-2)} = \frac{5}{2}$ So, the slope of the line is $\frac{5}{2}$.

Now, answering the questions:

4. The slope of a line parallel to this line will be the same, which is $\frac{5}{2}$.
5. The slope of a line perpendicular to this line is the negative reciprocal. So, it will be: $m_{\perpendicular} = -\frac{2}{5}$

Let me know if you want further details on this process! Here are five related questions:

1. How do you calculate the equation of the line using the slope and a point?
2. What does it mean for two lines to be perpendicular?
3. How do you find the y-intercept of a line if you know its slope and one point?
4. Can two lines with the same slope ever intersect?
5. How can you graph a line using just its slope and one point?

Tip: For any line in the form $y = mx + b$, the value $m$ represents the slope, and $b$ is the y-intercept.