Math Problem Statement
Solution
The problem asks to find the probability that a given score is less than 1.05 using a normal distribution. Here's a breakdown of the situation based on the image:
- The scores are normally distributed with a mean of 0 and a standard deviation of 1.
- The task is to determine which graph correctly represents the cumulative area under the curve to the left of , which corresponds to finding .
Standard Normal Distribution
For a standard normal distribution (mean = 0, standard deviation = 1), we need to find the cumulative probability for .
Using the Z-score table, .
This means that about 85.31% of the data lies below a Z-score of 1.05, so the correct graph should show an area under the curve to the left of that covers about 85% of the total area.
Graph Interpretation
Based on the question:
- The correct graph should shade a large portion of the left side of the curve (about 85%).
- The peak should be centered at , with a standard bell curve extending on both sides.
Graph C appears to match this description since it shows most of the area under the curve shaded to the left of , which is consistent with the solution from the Z-score table.
Answer:
The correct option is C.
Would you like further details on how this problem is solved or explanations of related concepts?
Here are five related questions you might find useful:
- How do you use a Z-score table to find probabilities?
- What is the standard normal distribution, and why is it important?
- How do you calculate the Z-score for a data point from any normal distribution?
- How do cumulative probabilities work in a normal distribution?
- What is the significance of the area under the curve in probability?
Tip: When working with normal distributions, the Z-score allows you to compare values from any normal distribution to the standard normal distribution.
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Math Problem Analysis
Mathematical Concepts
Probability
Normal Distribution
Z-Score
Formulas
Z = (X - μ) / σ
P(X < z)
Theorems
Standard Normal Distribution
Empirical Rule
Suitable Grade Level
Grades 10-12