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In the image you uploaded, the question asks you to find the missing numbers in a long division problem. The division work shows:

\[
213 \, R1 \quad \text{(R1 indicates the remainder is 1)}
\]
Dividing \( \boxed{?} \boxed{?} 8 \) by 14, with the quotient 213 and a remainder of 1.

### Step-by-step analysis of the long division:

1. **First step:**
   - 14 divides into \( ? \times 10^2 \) (represented by 2?8), starting with the first two digits.
   - From the quotient 213, the first digit is 2.
   - \( 14 \times 2 = 28 \) is subtracted from the first two digits (resulting in a 0).
   
2. **Second step:**
   - The next number in the dividend must be a number that, when combined with 0, allows division by 14.
   - The quotient (from the division of the next segment) is 1 (from 213).
   - \( 14 \times 1 = 14 \), subtracted to get a remainder of 0 again.

3. **Final step:**
   - We end up with a remainder of 1 after subtracting 42 from 43, confirming the remainder is correct.

### Finding the missing numbers:

- The missing numbers in the dividend are likely **9** and **4**, because the original number being divided seems to be **2984**.

Would you like further explanation on any of these steps?

### Follow-up questions:
1. How does long division work with larger dividends?
2. Can you always check your result using multiplication and addition?
3. What is the remainder in division, and why does it occur?
4. How can you predict how many digits will be in a quotient?
5. How do you perform division when the dividend is smaller than the divisor?

### Tip:
Always check division by multiplying the quotient by the divisor and adding the remainder.

What are the missing numbers in the dividend 2?8? in the work shown below? The problem involves a long division where 14 divides into 2?8? to give a quotient of 213 and a remainder of 1.

Learn how to find the missing numbers in a long division problem where 14 divides into 2?8? to give a quotient of 213 and a remainder of 1. This problem covers key arithmetic concepts and is suitable for students in Grades 4-6.

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