Math Problem Statement

find the missing length

Find the missing length.

Solution

PIL import Image from IPython.display import display

Load and display the user-uploaded image

image_path = "/mnt/data/1733675896594a7bbcb13.jpg" uploaded_image = Image.open(image_path) display(uploaded_image)The diagram shows a triangle with a parallel segment creating two proportional triangles. To find the missing length (?), we use the principle of similar triangles, which states that the ratios of corresponding sides are equal.

Given:

  • Larger triangle's vertical height: 3636
  • Smaller triangle's vertical height: 2020
  • Larger triangle's base segment: 2525
  • Smaller triangle's base segment: ??

Solution:

The ratio of the heights gives the ratio of the bases: Height of smaller triangleHeight of larger triangle=Base of smaller triangleBase of larger triangle\frac{\text{Height of smaller triangle}}{\text{Height of larger triangle}} = \frac{\text{Base of smaller triangle}}{\text{Base of larger triangle}}

Substitute the known values: 2036=?25\frac{20}{36} = \frac{?}{25}

Simplify: 59=?25\frac{5}{9} = \frac{?}{25}

Cross-multiply: 9?=5259 \cdot ? = 5 \cdot 25

Solve for ??: ?=125913.89? = \frac{125}{9} \approx 13.89

Final Answer:

The missing length is approximately 13.89 units.

Would you like more details, or have questions about this solution?


Related Questions:

  1. How does the concept of similar triangles apply to real-world problems?
  2. What happens to the proportions if the triangle's orientation is reversed?
  3. How can we verify if two triangles are truly similar?
  4. What other mathematical properties of triangles can be deduced from this setup?
  5. How does changing one dimension (e.g., height) affect the missing length?

Tip:

Always check for parallel lines or given ratios when solving problems involving similar triangles!

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Math Problem Analysis

Mathematical Concepts

Similar Triangles
Proportions

Formulas

Ratio of corresponding sides for similar triangles
\frac{height_{small}}{height_{large}} = \frac{base_{small}}{base_{large}}

Theorems

Principle of Similar Triangles

Suitable Grade Level

Grades 7-9