Math Problem Statement

The graph of a function h is shown. Find h(-2) and one value of x for which h(x) = -5.

Solution

Let's analyze the graph step by step to solve the two questions:

(a) Find h(2)h(-2):

To find h(2)h(-2), we look at the graph and locate where x=2x = -2. From the graph, at x=2x = -2, the value of h(x)h(x) corresponds to the point on the y-axis at that position.

Looking closely, at x=2x = -2, the graph shows that h(2)=4h(-2) = 4.

Thus, h(2)=4h(-2) = 4

(b) Find one value of xx for which h(x)=5h(x) = -5:

To find the value of xx for which h(x)=5h(x) = -5, we need to locate where the graph intersects the line y=5y = -5.

From the graph, it intersects the line y=5y = -5 at x=4x = -4. Thus, one value of xx for which h(x)=5h(x) = -5 is: x=4x = -4

Final Answers:

(a) h(2)=4h(-2) = 4

(b) x=4x = -4 when h(x)=5h(x) = -5

Would you like more details or further explanation?

Here are 5 related questions for further exploration:

  1. What would h(x)h(x) be for x=0x = 0?
  2. How can you find the vertex of the parabola from the graph?
  3. What is the axis of symmetry of the parabola?
  4. Is there any other xx-value for which h(x)=5h(x) = -5?
  5. How does the graph behave for large positive and negative values of xx?

Tip: When analyzing graphs, always check for key points like the vertex, intercepts, and symmetry to gain better insights into the function!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Graphing
Quadratic Functions
Function Analysis

Formulas

None required for this problem, as it's focused on graph interpretation

Theorems

None required, though knowledge of parabolas is helpful

Suitable Grade Level

Grades 7-9