Math Problem Statement

Use the graph of the function h(x) to find the following: h(0), h(4), solve h(x) = -1, and solve h(x) = 5.

Solution

Let's analyze the graph and answer the questions based on the function h(x)h(x):

a. h(0)h(0):

To find h(0)h(0), look at the value of the function when x=0x = 0. From the graph, at x=0x = 0, the value of h(x)h(x) is approximately 0.5. Thus, h(0)=0.5h(0) = 0.5.

b. h(4)h(4):

To find h(4)h(4), check the value of the function at x=4x = 4. At x=4x = 4, the graph shows an open circle at y=3y = 3, which means h(4)h(4) is not defined. Thus, h(4)h(4) is undefined.

c. Solve h(x)=1h(x) = -1:

To solve h(x)=1h(x) = -1, find the points where the graph of h(x)h(x) crosses y=1y = -1. From the graph, h(x)=1h(x) = -1 at x=1x = -1 and x=1x = 1. So, the solutions are x=1x = -1 and x=1x = 1.

d. Solve h(x)=5h(x) = 5:

To solve h(x)=5h(x) = 5, find the points where the graph of h(x)h(x) reaches y=5y = 5. From the graph, there is no point where the graph reaches y=5y = 5, so there is no solution for h(x)=5h(x) = 5. Thus, there is no solution.


Would you like more details or have any further questions?

Here are 5 related questions to explore:

  1. What are the zeros of the function h(x)h(x)?
  2. What is the range of the function based on the graph?
  3. Is the function h(x)h(x) continuous? Why or why not?
  4. What are the local maximum and minimum points of h(x)h(x)?
  5. Can you find the domain of the function?

Tip: When analyzing graphs of functions, look closely for open and closed circles to identify whether points are included or excluded from the function's values.

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Math Problem Analysis

Mathematical Concepts

Function evaluation
Graph analysis

Formulas

None required for this specific graph-based problem

Theorems

None required for this specific graph-based problem

Suitable Grade Level

Grades 9-12