To find the gradient (slope) and $y$-intercept, we need the equation of the line in the form:

$y = mx + c$

where:

• $m$ is the gradient (slope),
• $c$ is the $y$-intercept.

The expression given is $5x + 1$. However, it seems incomplete as it's not an equation yet, but let’s assume it’s part of an equation like $y = 5x + 1$.

In this case:

• The gradient $m$ is 5.
• The $y$-intercept $c$ is 1.

So, the gradient is 5, and the $y$-intercept is 1.

Would you like a more detailed explanation or have any questions about this?

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Here are some questions for further practice:

1. What would be the gradient and $y$-intercept of $y = -3x + 7$?
2. How do you find the $y$-intercept if the line equation is given in the form $ax + by = c$?
3. If the gradient of a line is zero, what does the graph of that line look like?
4. How does changing the gradient affect the steepness of a line?
5. If the $y$-intercept is negative, where would the line cross the $y$-axis?

Tip: To easily identify the gradient and $y$-intercept, rewrite equations in the $y = mx + c$ form whenever possible.