Math Problem Statement

If f(x) = cos(x^2 + x) then the value of f(2) is:

Solution

The given function is f(x)=cos(x2+x)f(x) = \cos(x^2 + x).

We are asked to find f(2)f(2), which means substituting x=2x = 2 into the function.

Steps:

  1. Substitute x=2x = 2 into the expression for f(x)f(x): f(2)=cos(22+2)=cos(4+2)=cos(6)f(2) = \cos(2^2 + 2) = \cos(4 + 2) = \cos(6)

Thus, the value of f(2)f(2) is cos(6)\cos(6), which corresponds to option (d).

Answer:

(d) cos(6)\cos(6)

Would you like a further breakdown of this calculation or have any related questions?

Here are 5 related questions for deeper understanding:

  1. What is the general formula for differentiating trigonometric functions like cosine?
  2. How does the chain rule apply to functions like f(x)=cos(g(x))f(x) = \cos(g(x))?
  3. What is the periodicity of the cosine function, and how does it affect values like cos(6)\cos(6)?
  4. Can you evaluate cos(6)\cos(6) using a calculator or approximate the value manually?
  5. What happens if you change the function to f(x)=sin(x2+x)f(x) = \sin(x^2 + x)? How would the answer change?

Tip: For functions involving trigonometric terms, always double-check your substitution steps carefully to avoid small mistakes.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Algebra

Formulas

cos(x^2 + x)
Substitution in functions

Theorems

Cosine function properties
Substitution theorem

Suitable Grade Level

Grades 9-12