Math Problem Statement

Q5.  In an arithmetic series the sum of the first, second and fourth terms are denoted by π‘ΊπŸ, π‘ΊπŸ, 𝒂𝒏𝒅 π‘ΊπŸ’ respectively. Now π‘ΊπŸ, π‘ΊπŸ, 𝒂𝒏𝒅 π‘ΊπŸ’ form three consecutive terms of a geometric sequence. Find the common ratio for this geometric sequence.*

1.5

3

4

2

None of the above

Solution

To solve this problem, let's break it down step by step:

Step 1: Define the terms of the arithmetic sequence.

Let the first term of the arithmetic sequence be aa and the common difference be dd.

  • The first term T1=aT_1 = a.
  • The second term T2=a+dT_2 = a + d.
  • The fourth term T4=a+3dT_4 = a + 3d.

Step 2: Define the sums S1S_1, S2S_2, and S4S_4.

  • S1=T1=aS_1 = T_1 = a
  • S2=T1+T2=a+(a+d)=2a+dS_2 = T_1 + T_2 = a + (a + d) = 2a + d
  • S4=T1+T2+T4=a+(a+d)+(a+3d)=3a+4dS_4 = T_1 + T_2 + T_4 = a + (a + d) + (a + 3d) = 3a + 4d

Step 3: Set up the geometric sequence condition.

Since S1S_1, S2S_2, and S4S_4 form a geometric sequence, the common ratio rr should satisfy the following relationship:

S2S1=S4S2\frac{S_2}{S_1} = \frac{S_4}{S_2}

Substituting the expressions we found:

2a+da=3a+4d2a+d\frac{2a + d}{a} = \frac{3a + 4d}{2a + d}

Step 4: Solve the equation for the common ratio rr.

Cross multiply and simplify:

(2a+d)2=a(3a+4d)(2a + d)^2 = a(3a + 4d)

Expanding both sides:

4a2+4ad+d2=3a2+4ad4a^2 + 4ad + d^2 = 3a^2 + 4ad

Simplifying:

4a2+d2=3a24a^2 + d^2 = 3a^2

This simplifies to:

a2=d2a^2 = d^2

Thus:

a=d or a=βˆ’da = d \text{ or } a = -d

Step 5: Determine the common ratio rr.

  • If a=da = d, substitute d=ad = a back into the expressions for S1S_1, S2S_2, and S4S_4 and find rr.
  • If a=βˆ’da = -d, substitute d=βˆ’ad = -a back into the expressions for S1S_1, S2S_2, and S4S_4 and find rr.

Let's now calculate both cases.For the given problem:

  • Case 1 (where a=da = d): The common ratio rr is 3.
  • Case 2 (where a=βˆ’da = -d): The common ratio rr is 1, but this does not match the options provided.

So, the correct answer based on the calculations is 3.

Would you like further details or have any questions? Here are some related questions for practice:

  1. How would the problem change if the arithmetic sequence started with a different first term?
  2. What happens if the geometric sequence condition doesn't hold? What does it imply about the arithmetic sequence?
  3. How would the solution change if you were given S3S_3 instead of S4S_4?
  4. How do different values of aa and dd affect the common ratio in the geometric sequence?
  5. Can the common ratio ever be negative in this context? Why or why not?

Tip: In sequences, always double-check if the terms you derive from one type of sequence (like arithmetic) can form another type (like geometric) under the given conditions.

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Math Problem Analysis

Mathematical Concepts

Arithmetic Sequences
Geometric Sequences
Common Ratio

Formulas

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Theorems

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Suitable Grade Level

High School