https://file.aiquickdraw.com/mathbot/file/1726393873293gci2qowy.jpg

To find the area of the triangles in the provided image, we can use the formula for the area of a triangle, which is \( \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \). Let's solve each problem step by step.

### Problem (e)
- **Base (b):** 26 m
- **Height (h):** 15 m (perpendicular distance)

\[ \text{Area} = \frac{1}{2} \times 26 \times 15 \]
\[ \text{Area} = \frac{1}{2} \times 390 \]
\[ \text{Area} = 195 \text{ m}^2 \]

### Problem (f)
- **Base (b):** 5 cm
- **Height (h):** 6 cm

\[ \text{Area} = \frac{1}{2} \times 5 \times 6 \]
\[ \text{Area} = \frac{1}{2} \times 30 \]
\[ \text{Area} = 15 \text{ cm}^2 \]

### Problem (g)
- **Base (b):** 42 m
- **Height (h):** 45 m

\[ \text{Area} = \frac{1}{2} \times 42 \times 45 \]
\[ \text{Area} = \frac{1}{2} \times 1890 \]
\[ \text{Area} = 945 \text{ m}^2 \]

### Problem (h)
- **Base (b):** 20 cm
- **Height (h):** 15 cm (perpendicular height)

\[ \text{Area} = \frac{1}{2} \times 20 \times 15 \]
\[ \text{Area} = \frac{1}{2} \times 300 \]
\[ \text{Area} = 150 \text{ cm}^2 \]

Would you like details on any specific step or have any other questions? Here are some related questions to further your understanding:

1. How do you determine the base and height of a triangle in non-right triangles?
2. Can the formula for the area of a triangle be used for all types of triangles?
3. What other methods can be used to find the area of a triangle if the base and height are not given?
4. How does the Pythagorean theorem help in finding the area of right-angled triangles?
5. How would you find the area of a triangle if you only know the lengths of all three sides?

**Tip:** When working with triangles, always ensure that the height is perpendicular to the base to correctly apply the area formula.

Find the area of the triangles shown in the image.

Learn how to calculate the area of various triangles using the formula 1/2 × base × height. This problem involves finding the area of right-angled triangles with given dimensions for base and height, suitable for students in Grades 6-8.

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