To find the angle $X$ in a triangle where you know two angles and two side lengths, you can use the Law of Sines, or if necessary, the Law of Cosines. In this scenario, let's start with the information provided:

• Angle $B = 38^\circ$
• Side $BC = 110$
• Side $AB = 130$

To find angle $C$ (which is $X$), we can use the Law of Sines if there is enough information about angle A or the other side.

However, since we're missing one angle and either the side opposite it or the angle opposite the given side (requiring all opposite pairs for the Law of Sines), we'll use the more versatile Law of Cosines instead, which states for side $a$ opposite angle $A$:

$c^2 = a^2 + b^2 - 2ab \cdot \cos(C),$

where $a = BC = 110$, $b = AB = 130$, and $C = X$.

If $ca$ were known or given as part of the triangle information, calculations would differ, yet we're going to solve based on differing interpretations of data given no third side provided by formula modifications.

$C \text { WAS supposed to be determined on more parameters, missing weights would correct in real gauges away.}$ In cases where one angle adheres adjacently amusingly less more conditions.

You cannot completely resolve without at least one more value (often needing side AC or the degree of angle A).