Math Problem Statement

Find the amplitude and period of y = 4 cos(2x + \u03C0/2).

Solution

It looks like you want to find the amplitude of the function given in the image. The function is:

y=4cos(2x+π2)y = 4 \cos\left( 2x + \frac{\pi}{2} \right)

To find the amplitude, we look at the coefficient in front of the cosine function.

Amplitude:

The amplitude of a cosine function y=Acos(Bx+C)y = A \cos(Bx + C) is given by the absolute value of AA. In this case, A=4A = 4.

So, the amplitude is:

Amplitude=4=4\text{Amplitude} = |4| = 4

Period:

The period of a cosine function is calculated as:

Period=2πB\text{Period} = \frac{2\pi}{|B|}

where BB is the coefficient of xx inside the cosine. Here, B=2B = 2, so the period is:

Period=2π2=π\text{Period} = \frac{2\pi}{2} = \pi

Thus, the amplitude is 4 and the period is π\pi.

Would you like more details or further explanations?

Here are some related questions you might find interesting:

  1. How does the amplitude affect the graph of the cosine function?
  2. What is the phase shift of the function given by y=4cos(2x+π2)y = 4 \cos(2x + \frac{\pi}{2})?
  3. How do you determine the period of a sine function?
  4. What happens if the coefficient AA is negative in a cosine function?
  5. How does the period of the cosine function change if BB is larger or smaller?

Tip: When solving for the amplitude, make sure to check the coefficient directly in front of the cosine (or sine) function.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Amplitude
Period of a Cosine Function

Formulas

Amplitude of y = A cos(Bx + C) is |A|.
Period of y = A cos(Bx + C) is 2\u03C0 / |B|.

Theorems

Amplitude and Period of Trigonometric Functions

Suitable Grade Level

Grades 9-12