Math Problem Statement
Solution
To solve the problem of finding all zeros of the polynomial , we follow these steps:
Step 1: Rational Root Theorem
The possible rational roots of the polynomial are the factors of the constant term (-3) divided by the factors of the leading coefficient (1). Thus, the possible roots are:
Step 2: Test Possible Roots
We substitute these possible roots into to see which one is a root.
- Test : Thus, is a root.
Step 3: Synthetic Division
Divide by using synthetic division:
1 & 1 & 3 & -1 & -3 \\ & & 1 & 4 & 3 \\ \hline & 1 & 4 & 3 & 0 \\ \end{array}$$ The quotient is $$x^2 + 4x + 3$$, so: $$P(x) = (x - 1)(x^2 + 4x + 3)$$ ### Step 4: Factor the Quadratic Factor $$x^2 + 4x + 3$$: $$x^2 + 4x + 3 = (x + 3)(x + 1)$$ ### Step 5: Write All Zeros The complete factorization is: $$P(x) = (x - 1)(x + 3)(x + 1)$$ Thus, the zeros are: $$x_1 = -3, \quad x_2 = -1, \quad x_3 = 1$$ ### Final Answer: The zeros of the polynomial are: $$x_1 = -3, \quad x_2 = -1, \quad x_3 = 1$$ Let me know if you'd like a detailed explanation of any step or have more questions! Here's a list of related questions: 1. What is the Rational Root Theorem, and how is it applied? 2. How does synthetic division work for polynomial division? 3. Why does factoring a quadratic give its roots? 4. Can this process be applied to higher-degree polynomials? 5. How can we confirm all roots satisfy the original polynomial? **Tip:** Always verify all roots by substituting them back into the polynomial to ensure accuracy.Ask a new question for Free
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Math Problem Analysis
Mathematical Concepts
Polynomial Zeros
Factoring Polynomials
Synthetic Division
Formulas
Rational Root Theorem
Factoring quadratic expressions
Theorems
Rational Root Theorem
Suitable Grade Level
Grades 9-12
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