To determine the zeros of the polynomial function from the given graph, we look for the points where the curve intersects the x-axis. These points are where the function equals zero (i.e., $y = 0$).

Observations:

• The graph intersects the x-axis at two points.
• These points appear to be approximately at $x = -1$ and $x = 1$.

Conclusion:

The zeros of the polynomial function are: $x = -1 \quad \text{and} \quad x = 1$

These values are solutions to the equation $f(x) = 0$, where $f(x)$ is the given polynomial.

Let me know if you'd like a deeper explanation or analysis, such as determining the exact equation of the parabola!

Here are five related questions:

1. What is the vertex of the polynomial function shown in the graph?
2. How do you determine if a parabola opens upward or downward from its graph?
3. Can you write the equation of this parabola using its vertex and zeros?
4. What is the axis of symmetry for this parabola?
5. How do you find the zeros of a polynomial function algebraically?

Tip: For a quadratic function in standard form $y = ax^2 + bx + c$, the zeros can be found using the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$.