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The image contains two equations where you are asked to find the **x** and **y** intercepts. The equations are:

1. \( y = 2 + 3x \)
2. \( y = \frac{x - 3}{2x - 8} \)

Let's go step by step for each one.

### 1. For the first equation: \( y = 2 + 3x \)

**Y-intercept**:  
The y-intercept occurs when \( x = 0 \).  
Substitute \( x = 0 \) into the equation:
\[
y = 2 + 3(0) = 2
\]
So, the y-intercept is \( (0, 2) \).

**X-intercept**:  
The x-intercept occurs when \( y = 0 \).  
Set \( y = 0 \) and solve for \( x \):
\[
0 = 2 + 3x \implies 3x = -2 \implies x = -\frac{2}{3}
\]
So, the x-intercept is \( \left(-\frac{2}{3}, 0\right) \).

---

### 2. For the second equation: \( y = \frac{x - 3}{2x - 8} \)

**Y-intercept**:  
The y-intercept occurs when \( x = 0 \).  
Substitute \( x = 0 \) into the equation:
\[
y = \frac{0 - 3}{2(0) - 8} = \frac{-3}{-8} = \frac{3}{8}
\]
So, the y-intercept is \( \left(0, \frac{3}{8}\right) \).

**X-intercept**:  
The x-intercept occurs when \( y = 0 \).  
Set \( y = 0 \) and solve for \( x \):
\[
0 = \frac{x - 3}{2x - 8}
\]
For this fraction to be 0, the numerator must be 0:
\[
x - 3 = 0 \implies x = 3
\]
So, the x-intercept is \( (3, 0) \).

---

### Summary:
1. **For \( y = 2 + 3x \):**
   - X-intercept: \( \left(-\frac{2}{3}, 0\right) \)
   - Y-intercept: \( (0, 2) \)
   
2. **For \( y = \frac{x - 3}{2x - 8} \):**
   - X-intercept: \( (3, 0) \)
   - Y-intercept: \( \left(0, \frac{3}{8}\right) \)

Would you like more details on these steps? Here are some related questions you might find interesting:

1. How can you graph these lines based on their intercepts?
2. How do you find intercepts for more complex functions?
3. What do vertical or horizontal lines imply for intercepts?
4. How can you solve for intercepts in quadratic equations?
5. Can there be more than one x-intercept for nonlinear equations?

**Tip:** When looking for intercepts, always remember that y-intercepts occur at \(x = 0\) and x-intercepts occur when \(y = 0\).

Learn how to find the x and y intercepts for linear equations such as y = 2 + 3x and rational functions like y = (x - 3)/(2x - 8). This problem covers key concepts in algebra, including intercepts for both linear and rational equations. Suitable for students in Grades 9-11.

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