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We are tasked with finding the x-intercept and y-intercept of the line described by the equation:

\[
3x - 2y = -12
\]

### 1. Finding the x-intercept:
The x-intercept occurs when \( y = 0 \). Let's substitute \( y = 0 \) into the equation:

\[
3x - 2(0) = -12
\]
\[
3x = -12
\]
\[
x = \frac{-12}{3} = -4
\]

So, the x-intercept is \( x = -4 \).

### 2. Finding the y-intercept:
The y-intercept occurs when \( x = 0 \). Let's substitute \( x = 0 \) into the equation:

\[
3(0) - 2y = -12
\]
\[
-2y = -12
\]
\[
y = \frac{-12}{-2} = 6
\]

So, the y-intercept is \( y = 6 \).

### Final Answer:
- **x-intercept**: \( x = -4 \)
- **y-intercept**: \( y = 6 \)

Would you like more details or further clarification?

Here are 5 related questions to extend this topic:
1. How do you find intercepts from a line in slope-intercept form?
2. Can a line have both x-intercepts and y-intercepts at the same point?
3. What do intercepts represent in real-world problems?
4. How can you graph a line using only the intercepts?
5. How do intercepts change if we modify the equation slightly?

**Tip**: When finding intercepts, always substitute the other variable as zero!

Find the x-intercept and y-intercept of the line: 3x - 2y = -12

Learn how to find the x- and y-intercepts of the line given by the equation 3x - 2y = -12. This problem covers basic algebraic concepts and is suitable for students in Grades 7-9.

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