To find the x-intercept and y-intercept of the equation $5x + 3y = 15$, we follow these steps:

1. Finding the x-intercept:

The x-intercept occurs when $y = 0$. To find the x-intercept, substitute $y = 0$ into the equation:

$5x + 3(0) = 15$ $5x = 15$ $x = \frac{15}{5} = 3$

So, the x-intercept is $(3, 0)$.

2. Finding the y-intercept:

The y-intercept occurs when $x = 0$. To find the y-intercept, substitute $x = 0$ into the equation:

$5(0) + 3y = 15$ $3y = 15$ $y = \frac{15}{3} = 5$

So, the y-intercept is $(0, 5)$.

Summary:

• x-intercept: $(3, 0)$
• y-intercept: $(0, 5)$

Would you like more details or have any questions?

Here are 5 related questions:

1. How do you graph a line using intercepts?
2. What does the slope of the line represent in this equation?
3. How do you rewrite the equation $5x + 3y = 15$ in slope-intercept form?
4. How would you find the intercepts of a vertical or horizontal line?
5. How can you check if a point is on the line represented by $5x + 3y = 15$?

Tip: Always substitute one variable as zero to easily find the intercepts of any linear equation.