To find the x-component $V_x$ of the given vector $\vec{V}$, we use the following equation:

$V_x = V \cdot \cos(\theta)$

Where:

• $V = 92.5 \, \text{m}$ (the magnitude of the vector)
• $\theta = 148^\circ$ (the angle measured counterclockwise from the positive x-axis)

Now let's calculate the x-component.The x-component of the vector is approximately $V_x = -78.44 \, \text{m}$.

Would you like further details or have any questions about this calculation?

Here are some related questions to deepen your understanding:

1. How would you calculate the y-component of this vector?
2. What happens to the x-component if the angle $\theta$ is changed to 90°?
3. Why is the x-component negative in this case?
4. Can you explain how the angle affects the direction of the vector components?
5. How would you use the Pythagorean theorem to verify the magnitude of the vector?

Tip: When using angles in trigonometric functions, always ensure whether they are in degrees or radians, as it impacts the calculation.