The problem asks to find the width $b$ of a rectangle given its length $l$ and area $A$. The formula for the area of a rectangle is:

$A = l \cdot b$

From the text:

• $l = 4.8 \, \text{m}$
• $A = 16.8 \, \text{m}^2$

Solving for $b$:

Rearrange the formula for $b$: $b = \frac{A}{l}$

Substitute the given values: $b = \frac{16.8}{4.8}$

Perform the division: $b = 3.5 \, \text{m}$

Final Answer:

The width of the rectangle is 3.5 meters.

Would you like further clarification or additional details?

Related Questions:

1. What is the formula for the perimeter of a rectangle, and how would you calculate it using the dimensions here?
2. If the length increased by 10%, how would the area change if the width stayed constant?
3. Can you find the diagonal of this rectangle using the Pythagorean theorem?
4. What is the relationship between the area and the aspect ratio (length-to-width ratio)?
5. How would the solution change if the area was given in square centimeters instead of square meters?

Tip:

Always check the units when solving geometry problems to ensure consistency throughout the calculations!