Given the function \( p(x) = 2x - 4 \), we want to find the values of \( p(-2) \) and \( p(0) \).

1. **Finding \( p(-2) \):**

   Substitute \( x = -2 \) into the function:

   \[
   p(-2) = 2(-2) - 4
   \]

   Simplify:

   \[
   p(-2) = -4 - 4 = -8
   \]

2. **Finding \( p(0) \):**

   Substitute \( x = 0 \) into the function:

   \[
   p(0) = 2(0) - 4
   \]

   Simplify:

   \[
   p(0) = 0 - 4 = -4
   \]

So, the results are:

- \( p(-2) = -8 \)
- \( p(0) = -4 \)

Would you like more details or have any questions?

Here are 5 related questions to explore further:

1. What is the value of \( p(1) \) using the same function?
2. How would the graph of \( p(x) = 2x - 4 \) look like?
3. What is the slope of the line represented by the function \( p(x) = 2x - 4 \)?
4. How would you find the x-intercept of the function \( p(x) = 2x - 4 \)?
5. How does the function change if the slope is modified to 3, i.e., \( p(x) = 3x - 4 \)?

**Tip:** To find \( p(x) \) at a specific value, substitute the value of \( x \) directly into the function equation and simplify.

Learn how to find the values of the function p(x) = 2x - 4 at specific points such as p(-2) and p(0). This problem covers linear functions and function notation, suitable for Grades 7-9 students.

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