This question is asking for the value of $c$ in a standard normal distribution where:

$P(Z > c) = 0.1949$

Steps to solve:

1. Identify the probability: Here, we are given that the probability $P(Z > c) = 0.1949$. This means the area to the right of $c$ under the standard normal curve is 0.1949.

2. Find the complement: Since the total area under the curve is 1, the area to the left of $c$ is: $P(Z \leq c) = 1 - 0.1949 = 0.8051$ So, $P(Z \leq c) = 0.8051$.

3. Use the Z-table or calculator: You can now look up the Z-value that corresponds to an area of 0.8051 in the cumulative distribution table for the standard normal distribution.

   From the Z-table, we find that: $c \approx 0.86$

Therefore, the value of $c$ is approximately 0.86 when rounded to two decimal places.

Would you like further clarification on any part of the solution? Here are some related questions for more practice:

1. What is the interpretation of the standard normal distribution?
2. How do you find $P(Z < c)$ from a Z-table?
3. Can you explain the relationship between probabilities and areas under the normal curve?
4. How do Z-scores help in finding probabilities?
5. What is the inverse cumulative distribution function?

Tip: Always check whether you're dealing with the upper tail (as in this case) or the lower tail when working with probabilities.