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To solve for \( f(0) - 7 \) given that \( f(x) = -2x - 3 \), we can follow these steps:

1. **Calculate \( f(0) \):**
   Substitute \( x = 0 \) into \( f(x) = -2x - 3 \).

   \[
   f(0) = -2(0) - 3 = -3
   \]

2. **Compute \( f(0) - 7 \):**
   Now, we subtract 7 from \( f(0) \).

   \[
   f(0) - 7 = -3 - 7 = -10
   \]

### Answer:
\[
f(0) - 7 = -10
\]

Would you like further details or have any questions?

Here are 5 additional related questions:
1. How would the solution change if \( f(x) \) had a different constant term?
2. What would be \( g(0) \) given \( g(x) = x^2 + 5x \)?
3. How do we interpret \( f(x) - g(x) \) for these functions?
4. What is the general approach for finding \( f(a) - b \) for any constants \( a \) and \( b \)?
5. How could this problem be extended if \( f(x) \) and \( g(x) \) were combined into a new function?

**Tip:** For any function \( f(x) = ax + b \), finding \( f(0) \) always gives the constant term \( b \) directly.

If f(x) = -2x - 3 and g(x) = x^2 + 5x, find the value of f(0) - 7.

Learn how to find the value of f(0) - 7 given f(x) = -2x - 3 and g(x) = x^2 + 5x with a clear solution. Suitable for middle school students, covering key concepts in algebra and function substitution.

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