Math Problem Statement

solve it using kcl

Refer the electrical circuit shown below. Find Va using KCL.

Solution

To solve for VaV_a in this circuit using Kirchhoff's Current Law (KCL), we first analyze the circuit layout and assign currents to each branch. Here's the step-by-step solution:

Step 1: Labeling Currents

Let's denote:

  • I1I_1: The current flowing from the 8V source, through the 125Ω resistor.
  • I2I_2: The current flowing from the 12V source through the 500Ω resistor connected to VaV_a.
  • I3I_3: The current flowing through the 250Ω resistor between the two branches.

Step 2: Set Up Node Equations at VaV_a

By KCL, the sum of currents entering a node equals the sum of currents leaving the node. We choose the node at VaV_a and write the KCL equation.

At VaV_a, the currents flowing into the node should equal the currents flowing out. We have: I1=I2+I3I_1 = I_2 + I_3

Step 3: Express Currents in Terms of Voltages

Using Ohm's law V=IRV = IR, we express each current in terms of VaV_a:

  1. Current I1I_1: I1=8VVa125ΩI_1 = \frac{8V - V_a}{125 \, \Omega}

  2. Current I2I_2: I2=12VVa500ΩI_2 = \frac{12V - V_a}{500 \, \Omega}

  3. Current I3I_3: I3=Va250ΩI_3 = \frac{V_a}{250 \, \Omega}

Step 4: Substitute Currents into the KCL Equation

Substitute the expressions for I1I_1, I2I_2, and I3I_3 into the KCL equation:

8Va125=12Va500+Va250\frac{8 - V_a}{125} = \frac{12 - V_a}{500} + \frac{V_a}{250}

Step 5: Clear the Denominator

To simplify, multiply through by the least common multiple of the denominators, which is 500:

4(8Va)=(12Va)+2Va4(8 - V_a) = (12 - V_a) + 2V_a

Expanding and simplifying:

324Va=12Va+2Va32 - 4V_a = 12 - V_a + 2V_a

Combine terms involving VaV_a:

324Va=12+Va32 - 4V_a = 12 + V_a

Add 4Va4V_a to both sides:

32=12+5Va32 = 12 + 5V_a

Subtract 12 from both sides:

20=5Va20 = 5V_a

Divide by 5:

Va=4VV_a = 4V

Solution

The voltage VaV_a is 4 volts.


Would you like further details or have any questions on specific steps?


Here are 5 related questions to deepen your understanding:

  1. How does KCL help in solving complex circuits with multiple sources?
  2. Why is it necessary to express all currents in terms of voltage when applying KCL?
  3. How would the solution change if one of the voltage sources had a different value?
  4. How can Kirchhoff's Voltage Law (KVL) be used in conjunction with KCL in circuit analysis?
  5. What are the effects of resistor values on the voltage at node VaV_a?

Tip: When solving circuits with multiple sources, consider solving simpler sub-circuits separately, if possible, and then combining results.

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Math Problem Analysis

Mathematical Concepts

Electrical Circuit Analysis
Kirchhoff's Current Law (KCL)
Ohm's Law

Formulas

Ohm's Law: V = IR
Kirchhoff's Current Law: Sum of currents at a node = 0

Theorems

Kirchhoff's Current Law (KCL)

Suitable Grade Level

Undergraduate (Introductory Electrical Engineering)