Math Problem Statement

The measurement of the unknown angle, rounded to the nearest degree, in the following triangle is:

The measurement of the unknown angle, rounded to the nearest degree, in the following triangle is:

Solution

To determine the unknown angle θ\theta in the given right triangle, we can use trigonometric relationships. Based on the given dimensions:

  • The adjacent side to θ\theta is 77.
  • The opposite side to θ\theta is 2424.

We can use the tangent function:

tan(θ)=oppositeadjacent=247\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} = \frac{24}{7}

  1. Compute tan1\tan^{-1} to find θ\theta:

θ=tan1(247)\theta = \tan^{-1}\left(\frac{24}{7}\right)

Let me calculate this.import math

Given values

opposite = 24 adjacent = 7

Calculate theta using arctan

theta_radians = math.atan(opposite / adjacent) theta_degrees = math.degrees(theta_radians) theta_degrees_rounded = round(theta_degrees)

theta_degrees_rounded7474successThe measurement of the unknown angle θ\theta is approximately 7474^\circ, rounded to the nearest degree.

Would you like a detailed breakdown of the trigonometric steps or further assistance? Here are some related questions to explore:

  1. What are the values of the other trigonometric ratios for this triangle?
  2. How would the angle change if the side lengths were doubled?
  3. Can you calculate the area of the triangle using these dimensions?
  4. What would the hypotenuse of this triangle be?
  5. How does the tangent function change for angles beyond 9090^\circ?

Tip: Always double-check the side labels (opposite, adjacent, hypotenuse) when using trigonometric functions. Mislabeling can lead to incorrect results.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Trigonometry
Right Triangles
Inverse Trigonometric Functions

Formulas

tan(θ) = opposite / adjacent
θ = tan⁻¹(opposite / adjacent)

Theorems

Pythagorean Theorem (implicitly used to validate the right triangle)

Suitable Grade Level

Grades 9-11