One number is 25 more than a second number. If there’s sum is  47 find the two numbers 

Let's solve the problem step by step.

Let the second number be \( x \).  
Then, the first number is \( x + 25 \).

According to the problem, the sum of the two numbers is 47. So we have:

\[
x + (x + 25) = 47
\]

Simplifying this equation:

\[
2x + 25 = 47
\]

Subtract 25 from both sides:

\[
2x = 22
\]

Divide both sides by 2:

\[
x = 11
\]

So, the second number is 11. The first number, being 25 more than the second, is:

\[
11 + 25 = 36
\]

Thus, the two numbers are **11 and 36**.

Would you like further details or have any questions?

Here are 5 related questions:
1. If the first number was 30 more than the second, and their sum was 50, what would the numbers be?
2. What if the sum of the two numbers was 60 instead of 47, and the first number was still 25 more than the second?
3. How would the equation change if the first number was instead 25 less than the second number?
4. Can you solve a similar problem where the difference between the two numbers is given instead of the sum?
5. What if the first number was double the second number, and their sum was 75?

**Tip:** When solving word problems involving sums and differences, clearly define variables to represent the unknowns, then translate the word problem into an equation.

Learn how to solve a problem where one number is 25 more than another, and their sum is 47. Follow a step-by-step solution to find the two numbers involved. Suitable for students in Grades 6-8.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation