The problem asks for three consecutive odd integers whose sum is 69.

Solution:

1. Let the first odd integer be $x$.

2. The next consecutive odd integers are $x + 2$ and $x + 4$.

3. The sum of these three integers is given as: $x + (x + 2) + (x + 4) = 69$

4. Simplify the equation: $3x + 6 = 69$

5. Subtract 6 from both sides: $3x = 63$

6. Divide by 3: $x = 21$

Thus, the three integers are: $21, 23, \text{and } 25$

Final Answer:

The three consecutive odd integers are 21, 23, and 25.

Do you need further explanation or a breakdown of the solution?
Here are 5 related questions for practice:

1. What are three consecutive even integers whose sum is 72?
2. Find three consecutive integers whose sum is 105.
3. What is the sum of four consecutive odd integers starting from 15?
4. If the sum of three consecutive numbers is 54, what are the numbers?
5. Write an equation for four consecutive integers whose sum is 98.

Tip: When solving problems with consecutive integers, use expressions like $x, x+2, x+4, \dots$ for odd or even integers. This keeps the calculations organized.